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  • Exam Code: SPLK-1003
  • Exam Name: Splunk Enterprise Certified Admin
  • Version: V15.35     Q & A: 208 Questions and Answers

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NEW QUESTION: 1
Normalizing data within a database could includes all or some of the following except which one?
A. Eliminates functional dependencies on a partial key by putting the fields in a separate table from those that are dependent on the whole key
B. Eliminated Functional dependencies on non-key fields by putting them in a separate table. At this level, all non-key fields are dependent on the primary key.
C. Eliminate duplicative columns from the same table.
D. Eliminating duplicate key fields by putting them into separate tables.
Answer: D
Explanation:
1. Eliminate duplicative columns from the same table.
2 . Eliminates functional dependencies on a partial key by putting the fields in a separate table from those that are dependent on the whole key.
3 . Eliminated Functional dependencies on non-key fields by putting them in a separate table. At this level, all non-key fields are dependent on the primary key.
In creating a database, normalization is the process of organizing it into tables in such a way that the results of using the database are always unambiguous and as intended.
Normalization may have the effect of duplicating data within the database and often results in the creation of additional tables. (While normalization tends to increase the duplication of data, it does not introduce redundancy, which is unnecessary duplication.) Normalization is typically a refinement process after the initial exercise of identifying the data objects that should be in the database, identifying their relationships, and defining the tables required and the columns within each table.
A simple example of normalizing data might consist of a table showing:
Customer Item purchased Purchase price
Thomas Shirt $40
Maria Tennis shoes $35
Evelyn Shirt $40
Pajaro Trousers $25
If this table is used for the purpose of keeping track of the price of items and you want to delete one of the customers, you will also delete a price. Normalizing the data would mean understanding this and solving the problem by dividing this table into two tables, one with information about each customer and a product they bought and the second about each product and its price. Making additions or deletions to either table would not affect the other.
Normalization degrees of relational database tables have been defined and include:
First normal form (1NF). This is the "basic" level of normalization and generally corresponds to the definition of any database, namely:
It contains two-dimensional tables with rows and columns.
Each column corresponds to a sub-object or an attribute of the object represented by the entire table.
Each row represents a unique instance of that sub-object or attribute and must be different in some way from any other row (that is, no duplicate rows are possible).
All entries in any column must be of the same kind. For example, in the column labeled
"Customer," only customer names or numbers are permitted.
An entity is in First Normal Form (1NF) when all tables are two-dimensional with no repeating groups.
A row is in first normal form (1NF) if all underlying domains contain atomic values only. 1NF eliminates repeating groups by putting each into a separate table and connecting them with a one-to-many relationship. Make a separate table for each set of related attributes and uniquely identify each record with a primary key.
Eliminate duplicative columns from the same table.
Create separate tables for each group of related data and identify each row with a unique column or set of columns (the primary key).
Second normal form (2NF). At this level of normalization, each column in a table that is not a determiner of the contents of another column must itself be a function of the other columns in the table. For example, in a table with three columns containing customer ID, product sold, and price of the product when sold, the price would be a function of the customer ID (entitled to a discount) and the specific product.
An entity is in Second Normal Form (2NF) when it meets the requirement of being in First
Normal Form (1NF) and additionally:
Does not have a composite primary key. Meaning that the primary key can not be subdivided into separate logical entities.
All the non-key columns are functionally dependent on the entire primary key.
A row is in second normal form if, and only if, it is in first normal form and every non-key attribute is fully dependent on the key.
2NF eliminates functional dependencies on a partial key by putting the fields in a separate table from those that are dependent on the whole key. An example is resolving many:many relationships using an intersecting entity
Third normal form (3NF). At the second normal form, modifications are still possible because a change to one row in a table may affect data that refers to this information from another table. For example, using the customer table just cited, removing a row describing a customer purchase (because of a return perhaps) will also remove the fact that the product has a certain price. In the third normal form, these tables would be divided into two tables so that product pricing would be tracked separately.
An entity is in Third Normal Form (3NF) when it meets the requirement of being in Second
Normal Form (2NF) and additionally:
Functional dependencies on non-key fields are eliminated by putting them in a separate table. At this level, all non-key fields are dependent on the primary key.
A row is in third normal form if and only if it is in second normal form and if attributes that do not contribute to a description of the primary key are move into a separate table. An example is creating look-up tables.
Domain/key normal form (DKNF). A key uniquely identifies each row in a table. A domain is the set of permissible values for an attribute. By enforcing key and domain restrictions, the database is assured of being freed from modification anomalies. DKNF is the normalization level that most designers aim to achieve.
References:
KRUTZ, Ronald L. & VINES, Russel D., The CISSP Prep Guide: Mastering the Ten
Domains of Computer Security, 2001, John Wiley & Sons, Page 47.
and
http://psoug.org/reference/normalization.html
and
Tech Target SearcSQLServer at:
http://searchsqlserver.techtarget.com/definition/normalization?vgnextfmt=print

NEW QUESTION: 2
The Moore Corporation is considering the acquisition of a new machine. The machine can be purchased
for $90,000; it will cost $6,000 to transport to Moore's plant and $9,000 to install. It is estimated that the
machine will last 10 years, and it is expected to have an estimated salvage value of $5,000. Over its
1 0-year life, the machine is expected to produce 2,000 units per year with a selling price of $500 and
combined material and labor costs of $450 per unit. Federal tax regulations permit machines of this type
to be depreciated using the straight-line method over 5 years with no estimated salvage value. Moore has
a marginal tax rate of 40 percent.
What is the net cash flow for the tenth year of the project that Moore Corporation should use in a capital
budgeting analysis?
A. $68,400
B. $60,000
C. $63,000
D. $81,000
Answer: C
Explanation:
Choice "c" is correct. $63,000 net cash flow for the tenth year.

Alternate Computation:
In year 10, Moore will generate a $100,000 profit from the incremental sales (2000 units * ($500 -$450)).
This profit will be taxed at 40%, so the net after-tax increase in cash flow is $60,000. The machine is fully
depreciated in year 10 because it was depreciated over a 5-year life. The tax basis of the machine is zero
on the date Moore receives a $5,000 salvage value for the machine. The gain on the machine of $5,000
($5,000 SV $0 Basis) is taxed at 40%, or $2,000 in total tax outflow for the gain, so the net inflows on the
salvage is $3,000. Therefore, the total after-tax cash flows in year 10 for the new machine is $60,000 +
$ 3,000 = $63,000.

NEW QUESTION: 3
Drag and drop each statement about AAA from the left onto the correct AAA mechanism on the right

Answer:
Explanation:


NEW QUESTION: 4
The best practice for ensuring high I/O performance is
A. Making the logical volumes the same size as the physical disk.
B. Spreading the logical volumes across all logical disks using striping.
C. Spreading the logical volumes across all logical disks using concatenation.
D. Dedicating the physical disks to logical volumes.
Answer: B

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