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NEW QUESTION: 1
Sie möchten die konzerninterne Vermögensübertragung nur nach IFRS buchen. Welche Objekte können Sie in der Umbuchung angeben, um dies zu erreichen? Hinweis: Auf diese Frage gibt es 2 richtige Antworten.
A. Transaktionstyp
B. Bewertungsbereich
C. Rechnungslegungsgrundsatz
D. Hauptbuchgruppe
Answer: C,D

NEW QUESTION: 2
Who is responsible for the following tasks?
*Secure the scene
*Ensure that it is maintained in a secure state until the Forensic Team arrives
*Make notes about the scene that will eventually be handed over to the Forensic Team
A. Non-forensics staff
B. System administrators
C. Lawyers
D. Local managers or other non-forensic staff
Answer: A

NEW QUESTION: 3
SQL Server 2014 Enterprise Editionを使用している。
データベースにAuditDataという名前のパーティションテーブルが含まれています。 AuditDataは年ごとに分割されています。 パーティション1には、2010年以前のデータが含まれています。
経営陣は、2010年以前のすべてのAUDITDATAレコードをアーカイブすることを決定しました。
経営陣は、レコードをデータベースから完全に削除し、zip形式のテキストファイルとしてバックアップチームに提供することを望んでいます。 データはもうデータベースに存在してはいけません。
環境のパフォーマンス低下に対する許容度はほとんどありません。 最小限のシステムリソースを使用して、AuditDataテーブルから2010年以前のデータをすべて削除する必要があります。 必要なSQLアクションを正しい順序で選択して配置して、ソリューションを開発してください。
あなたはすべての行動を必要としないかもしれません。

Answer:
Explanation:

Explanation

Note:
- Create a new partitioned table with the partition function you want, and then insert the data from the old table into the new table by using an INSERT INTO...SELECT FROM statement.
- SPLIT RANGE ( boundary_value )
Adds one partition to the partition function. boundary_value determines the range of the new partition, and must differ from the existing boundary ranges of the partition function. Based on boundary_value, the Database Engine splits one of the existing ranges into two.
Of these two, the one where the new boundary_value resides is considered the new partition.
- BCP can be used top produce the zipped text file.
- Example: plitting a partition of a partitioned table or index into two partitions The following example creates a partition function to partition a table or index into four partitions.
ALTER PARTITION FUNCTION splits one of the partitions into two to create a total of five partitions.
CREATE PARTITION FUNCTION myRangePF1 (int)
AS RANGE LEFT FOR VALUES ( 1, 100, 1000 );
GO
-Split the partition between boundary_values 100 and 1000
-to create two partitions between boundary_values 100 and 500
--and between boundary_values 500 and 1000.
ALTER PARTITION FUNCTION myRangePF1 ()
SPLIT RANGE (500);