EC-COUNCIL 212-89 Latest Exam Fee, Exam 212-89 Simulator | Exam 212-89 Questions Pdf - Sapsam

  • Exam Code: 212-89
  • Exam Name: EC Council Certified Incident Handler (ECIH v3)
  • Version: V15.35     Q & A: 208 Questions and Answers

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NEW QUESTION: 1
Which of the following statement about gratuitous ARP packet are true?
A. A system can determine whether conflicting IP addresses are used by sending a gratuitous ARP packet
B. A gratuitous ARP packet uses the same format as an ARP reply packet
C. A gratuitous ARP packet can help to update an IP address
D. A gratuitous ARP packet uses the same format as an ARP request packet
Answer: A,D

NEW QUESTION: 2
設定値
VMサイズD3
保管場所ドライブE
保管タイプ標準
Tempdbの場所ドライブC
このインスタンスの作業負荷は、tembdb負荷です。
tempdbデータベースのパフォーマンスを最大限に引き出す必要があります。
解決策:GSシリーズVMを使用して、tempdbデータベースを付属のPremiumストレージに保存します。
これは目標を達成していますか?
A. いいえ
B. はい
Answer: A
Explanation:
For VMs that support Premium Storage (DS-series, DSv2-series, and GS-series), we recommend storing TempDB on a disk that supports Premium Storage with read caching enabled. There is one exception to this recommendation; if your TempDB usage is write-intensive, you can achieve higher performance by storing TempDB on the local D drive, which is also SSD-based on these machine sizes.
References:
https://docs.microsoft.com/en-us/azure/virtual-machines/windows/sql/virtual-machines-windows-sql-performance

NEW QUESTION: 3
For Oracle database to do online RMAN physical backups, you need oracle to run in _____ mode; To restore
data files, you need to start the Oracle____(Fill in the blanks multiple choice)
A. nomount
B. Non-archiving
C. mount
D. Archiving
Answer: C,D

NEW QUESTION: 4
Which two options are ways in which an OSPFv3 router handles hello packets with a clear address-family bit? (Choose two.)
A. IPv4 unicast packets are discarded.
B. IPv6 unicast packets are discarded.
C. IPv4 unicast packets are forwarded.
D. IPv6 unicast packets are forwarded.
Answer: A,D
Explanation:
A typical distance vector protocol saves the following information when computing the best path to a destination: the distance (total metric or distance, such as hop count) and the vector (the next hop). For instance, all the routers in the network in Figure 1 are running Routing Information Protocol (RIP). Router Two chooses the path to Network A by examining the hop count through each available path.

Since the path through Router Three is three hops, and the path through Router One is two hops, Router Two chooses the path through One and discards the information it learned through Three. If the path between Router One and Network A goes down, Router Two loses all connectivity with this destination until it times out the route of its routing table (three update periods, or 90 seconds), and Router Three re-advertises the route (which occurs every 30 seconds in RIP). Not including any hold-down time, it will take between 90 and 120 seconds for Router Two to switch the path from Router One to Router Three.
EIGRP, instead of counting on full periodic updates to re-converge, builds a topology table from each of its neighbor's advertisements (rather than discarding the data), and converges by either looking for a likely loop-free route in the topology table, or, if it knows of no other route, by querying its neighbors. Router Two saves the information it received from both Routers One and Three. It chooses the path through One as its best path (the successor) and the path through Three as a loop-free path (a feasible successor). When the path through Router One becomes unavailable, Router Two examines its topology table and, finding a feasible successor, begins using the path through Three immediately.
Reference: http://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routingprotocol-eigrp/16406-eigrp-toc.html

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