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NEW QUESTION: 1
Which of the following characterizes the cost of faults?
A. They are cheapest to find in the early development phases and the most expensive to fix in the latest test phases.
B. Faults are cheapest to find in the early development phases but the most expensive to fix then.
C. Although faults are most expensive to find during early development phases, they are cheapest to fix then.
D. They are easiest to find during system testing but the most expensive to fix then.
Answer: A

NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung, mit der die angegebenen Ziele erreicht werden können. Einige Fragensätze haben möglicherweise mehr als eine richtige Lösung, während andere möglicherweise keine richtige Lösung haben.
Nachdem Sie eine Frage in diesen Abschnitten beantwortet haben, können Sie NICHT mehr darauf zurückkommen. Infolgedessen werden diese Fragen nicht im Überprüfungsbildschirm angezeigt.
Sie verwalten einen Dateiserver, auf dem Windows Server 2016 ausgeführt wird. Der Dateiserver enthält die Volumes, die wie in der folgenden Tabelle gezeigt konfiguriert sind.

Sie müssen DevFiles mithilfe der BitLocker-Laufwerkverschlüsselung (ButLocker) verschlüsseln.
Lösung: Sie führen das Cmdlet Lock-BitLocker aus.
Erfüllt dies das Ziel?
A. Nein
B. Ja
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/powershell/module/bitlocker/lock-bitlocker?view=win10-ps

NEW QUESTION: 3
View the exhibit and examine the descriptions of the DEPTand LOCATIONStables.

You want to update the CITYcolumn of the DEPTtable for all the rows with the corresponding value in the CITYcolumn of the LOCATIONStable for each department.
Which SQL statement would you execute to accomplish the task?
A. UPDATE dept d
SET city = (SELECT city
FROM locations l)
WHERE d.location_id = l.location_id;
B. UPDATE dept d
SET city = ALL (SELECT city
FROM locations l
WHERE d.location_id = l.location_id);
C. UPDATE dept d
SET city = (SELECT city
FROM locations l
WHERE d.location_id = l.location_id);
D. UPDATE dept d
SET city = ANY (SELECT city
FROM locations l)
Answer: C