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NEW QUESTION: 1
사용자는 고객에 대한 입금을 생성하고 지불할 개의 송장을 선택합니다. 사용자가 결제를 게시하려고 하면 첨부된 스크린 샷에 표시된 시스템 메시지가 나타납니다.
이 시스템 메시지의 가능한 이유는 무엇입니까? 참고이 질문에 대한 두 가지 답변이 있습니다.

A. 인보이스가 아직 만료되지 않았습니다
B. 사용자가 결제 수단을 선택하지 않았습니다
C. 고객이 외화를 사용하고 환율이 설정되지 않았습니다.
D. 지불 수단 창의 금액이 총 송장 금액과 일치하지 않습니다
Answer: B,D

NEW QUESTION: 2
An audit trail is a category of what control?
A. System, Manual
B. Detective, Technical
C. Detective, Manual
D. User, Technical
Answer: B
Explanation:
Detective Technical Controls warn of technical Access Control violations. Under this category you would find the following: Audit trails Violation reports Intrusion detection system Honeypot

NEW QUESTION: 3
You are implementing an ASP.NET web application.The application defines the following classes. public class Person {
public String Name{get; set;} publicIList<Address> Addresses{get;set;} }
public class Address
{ public String AddressType{get; set;} public string AddressValue{get;set;}
}
The applicaction must generate XML from personList, wich is a collection of Person instances.The following
XML is an example of the schema than the generated XML must use.
<Persons>
<Person Name="John Doe">
<Address Email="[email protected]"/>
<Address AlternativeEmail="[email protected]"/>
<Address MSNInstanceMessenger="[email protected]"/>
</Person>
.....
</Persons>
You need to generate the XML.
Wich code segment should you use?
A. var XML= new XElement("Persons",
from person in personList
Select (new XElement("Persons",
newXAttribute("Name", person.Name))));
B. var XML= new XElement("Persons", from person in personList
Select (new XElement("Persons",
newXElement("Name", person.Name),
from addr in person.Addresses
select new XElement("Address",
newXElement(addr.AddressType,
addr.AddressValue)))));
C. var XML= new XAttribute("Persons", from person in personList
Select (new XElement("Persons",
newXAttribute("Name", person.Name),
from addr in person.Addresses
select new XAttribute("Address",
newXAttribute(addr.AddressType,
addr.AddressValue)))));
D. var XML= new XElement("Persons", from person in personList
Select (new XElement("Person",
newXAttribute("Name", person.Name),
from addr in person.Addresses
select new XElement("Address",
newXAttribute(addr.AddressType,
addr.AddressValue)))));
Answer: D