Exam JN0-363 Cost | Juniper JN0-363 Pass Test & Free JN0-363 Pdf Guide - Sapsam

  • Exam Code: JN0-363
  • Exam Name: Service Provider Routing and Switching, Specialist (JNCIS-SP)
  • Version: V15.35     Q & A: 208 Questions and Answers

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NEW QUESTION: 1
When entering customer information, an e-mail address is required. Which test design technique can be used
to test this?
A. Process Cycle Test
B. Data Combination Test
C. Syntactic Test
Answer: C

NEW QUESTION: 2
Click the Exhibit button.

Which statement is true regarding the output shown in the exhibit?
A. The configuration supports IPv6 unicast routes.
B. The configuration supports IPv4 multicast routes.
C. The configuration supports IPv6 multicast routes.
D. The configuration supports IPv4 unicast routes.
Answer: A
Explanation:
By default, OSPFv3 supports unicast IPv6 routes, but you can configure OSPFv3 to support multiple address families. To support an address family other than unicast IPv6, you configure a realm that allows OSPFv3 to advertise IPv4 unicast, IPv4 multicast, or IPv6 multicast routes.
Example of a configuration which support both Ipv4 and Ipv6 prefixes:
user@host# show protocols ospf3
realm ipv4-unicast {
area 0.0.0.0 {
interface fe-0/1/0.0;
}
}
area 0.0.0.0 {
interface fe-0/1/0.0;
}
References: http://www.juniper.net/documentation/en_US/junos15.1/topics/topic- map/ospfv3-multiple-address-families.html

NEW QUESTION: 3

A. The quantity in Column B is greater;
B. The relationship cannot be determined from the information given.
C. The quantities are equal;
D. The quantity in Column A is greater;
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Quantity A (ad) is a negative fractional number greater than a and approaching zero (0). Similarly, Quantity B (bc) is a negative fractional number greater than b and approaching zero (0). But ad must be less than cd (that is, further to the left than cd on the number line). Why? If a and b were both multiplied by c (a positive number), the inequality between a and b (a <b) would remain unchanged: ac < bc. It makes sense that if a is ultiplied instead by a positive number D that is greater than c, then the inequality between a and b not only remains the same but actually increases. In any event, ad < bc

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