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NEW QUESTION: 1
Which IBM software product used by IBM Spectrum Scale moves infrequently accessed data from disk to tape?
A. IBM Spectrum Virtualize
B. IBM Spectrum Accelerate
C. IBM Spectrum Archive
D. IBM Spectrum Control
Answer: C

NEW QUESTION: 2
You want to understand which SQL statements have been executing using Smart Scan capabilities. Where can you look for this information?
A. The hints used in a SQL statement
B. You can infer from the performance of the statement.
C. Query statistics from the V$ views
D. With the CELLCLI SMART.SQL statement
Answer: C
Explanation:
The Exadata storage provides several unique performance-enhancing features including smart scan, storage index and Exadata Hybrid Columnar Compression. Monitoring these features can be easily done via the Gv$ performance views or Oracle Enterprise Manager.
You can check if smart scan offloading has taken place or not and how much data got reduced by querying either the V$ views or by using the SQL Monitoring capabilities of Enterprise Manager. For example you can query IO_CELL_OFFLOAD_ELIGIBLE_BYTES from V$SQL to see if you query is eligible for query offload.

http://www.oracle.com/technetwork/middleware/bi-foundation/twp-dw-best-practices-workloadmgmt-157666.pdf

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int () const { return val;} };
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
struct Add : public binary_function<B, B, B> {
B operator() (const B & a, const B & b) const {
return a+b; } };
int main() {
B t[]={1,2,3,4,5,6,7,8,9,10};
vector<B> v1(t, t+10);
vector<B> v2(10);
transform(v1.begin(), v1.end(), v2.begin(), bind1st(Add(), 1));
for_each(v2.rbegin(), v2.rend(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 10 9 8 7 6 5 4 3 2 1
B. 1 2 3 4 5 6 7 8 9 10
C. 11 10 9 8 7 6 5 4 3 2
D. compilation error
E. 2 3 4 5 6 7 8 9 10 11
Answer: C