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NEW QUESTION: 1
Topic 6, Ticket 4 : BGP Neighbor
Topology Overview (Actual Troubleshooting lab design is for below network design)
Client Should have IP 10.2.1.3
EIGRP 100 is running between switch DSW1 & DSW2
OSPF (Process ID 1) is running between R1, R2, R3, R4
Network of OSPF is redistributed in EIGRP
BGP 65001 is configured on R1 with Webserver cloud AS 65002
HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the
ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside
(209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1
and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the
underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a `proof-of-concept' on several
implementations. This involved changing the configuration on one or more of the devices. You will be
presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and
solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution


Client is unable to ping IP 209.65.200.241
Answer:
Explanation:
Solution Steps need to follow as below:
When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4 ipconfig ----Client will be receiving IP address 10.2.1.3
IP 10.2.1.3 will be able to ping from R4 , R3, R2, R1
Look for BGP Neighbourship Sh ip bgp summary ----- No O/P will be seen
Check for interface IP & ping IP 209.65.200.225 ---- Reply will be received from Webserver interface
Look for peering IP address via sh run on R1 interface serial 0/0/1
Since we are receiving icmp packets from Webserver interface on R1 so peering IP address under router BGP is configured wrong IP but with correct AS nos.
Change required: On R1 under router BGP Change neighbor 209.56.200.226 remote-as 65002 statement to neighbor 209.65.200.226 remote-as 65002

So in ticket Answer to the fault condition will be as below for

NEW QUESTION: 2
Which two components are required by HP JetAdvantage Secure Print?
A. Device Scout and Usage Scout
B. Print Scout and Device Scout
C. Print Scout and Scanner Scout
D. Discovery Scout and Setup Scout
Answer: D

NEW QUESTION: 3
John works as a C programmer. He develops the following C program:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
int buffer(char *str) {
char buffer1[10];
strcpy(buffer1, str);
return 1;
}
int main(int argc, char *argv[]) {
buffer (argv[1]);
printf("Executed\n");
return 1;
}
His program is vulnerable to a __________ attack.
A. Denial-of-Service
B. Cross site scripting
C. SQL injection
D. Buffer overflow
Answer: D
Explanation:
This program takes a user-supplied string and copies it into 'buffer1', which can hold up to 10 bytes of data. If a user sends more than 10 bytes, it would result in a buffer overflow.