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NEW QUESTION: 1
ファイルシステムのソフト制限クォータを超えました。 データに関して何が起こると思いますか
アクセス？
A. ソフト制限に達すると、ハード制限に達するまで猶予期間がカウントダウンされます。 新しいデータは
ハード制限に達していない限り、記述してください。
B. ソフト制限に達すると、ファイルシステムまたはディレクトリに新しいデータを追加できません。
C. ソフト制限を超えたままで猶予期間が終了した場合、新しいデータを追加することはできません
特定のファイルシステムまたはディレクトリ。
D. ソフト制限を超えたままで猶予期間が終了した場合、特定のデータに新しいデータを追加できます
ディレクトリ。 システムは、猶予期間が終了したことを警告します。
Answer: A

NEW QUESTION: 2
조직에는 버지니아, 캐나다 및 시드니 지역에 각각 VPC가 포함된 3 개의 AWS 계정이 있습니다. 조직은 이러한 계정의 사용 가능한 모든 Elastic IP 주소 (EIP)가 규정 준수 및 비용 최적화를 위해 지정된 모든 지역에서 ENIM (elastic network interface)을 사용하거나 Amazon EC2 인스턴스에 연결되어 있는지 확인하려고 합니다.
다음 중 최소한의 관리 오버 헤드를 가진 요구 사항을 충족하는 것은 어느 것입니까?
A. AWS CloudFormation StackSets를 사용하여 모든 계정 및 지역에 AWS Config EIP 연결 규칙을 배포하여 연결되지 않은 EIP 및 사용되지 않는 EIP를 찾습니다.
B. Amazon CloudWatch Events 규칙을 사용하여 3 개 지역의 각 계정에서 AWS Lambda 기능을 예약하여 연결되지 않은 EIP 및 사용되지 않는 EIP를 찾습니다.
C. CloudWatch 이벤트 버스를 사용하여 연결되지 않은 미사용 EIP를 찾기 위해 세 지역의 각 계정에서 람다 기능을 예약합니다.
D. 연결되지 않은 EIP 및 사용되지 않은 EIP를 찾으려면 세 가지 계정의 각 영역에 AWS 관리 EIP 연결 AWS 구성 규칙을 추가하십시오.
Answer: D

NEW QUESTION: 3
CORRECT TEXT
You create a table by using the following Transact-SQL Statement:

You need to return a result set that has a single column named DisplayInformation. The result set must contain the Name value if the Name value is NOT NULL, otherwise the result set must contain the SubName value.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within the code that has been provided as well as below it.


Use the Check Syntax button to verify your work. Any syntax or spelling errors will be reported by line and character position.
Answer:
Explanation:
SELECT IIF (Name IS NOT NULL, Name, SubName)
Explanation:
Update line 1 to get the following:
SELECT IIF (Name IS NOT NULL, Name, SubName)
FROM Products;
IIF returns one of two values, depending on whether the Boolean expression evaluates to true or false in SQL Server.
Syntax: IIF ( boolean_expression, true_value, false_value )
If the value of expression is NULL, IS NULL returns TRUE; otherwise, it returns FALSE.
If the value of expression is NULL,IS NOT NULL returns FALSE; otherwise, it returns TRUE.
To determine whether an expression is NULL, use IS NULL or IS NOT NULL instead of comparison operators (such as = or !=). Comparison operators return UNKNOWN when either or both arguments are NULL References:https://msdn.microsoft.com/en-us/library/hh213574.aspx
https://msdn.microsoft.com/en-us/library/ms188795.aspx