PT0-002 Exam Cram, Valid PT0-002 Test Simulator | Study PT0-002 Test - Sapsam

  • Exam Code: PT0-002
  • Exam Name: CompTIA PenTest+ Certification
  • Version: V15.35     Q & A: 208 Questions and Answers

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NEW QUESTION: 1

A. Option B
B. Option C
C. Option A
D. Option D
Answer: D

NEW QUESTION: 2
スイッチがすべてのポートにフレームをフラッディングするのはなぜですか?
A. フレームの送信元と宛先のMACアドレスが同じ
B. フレームの送信元MACアドレスが不明です
C. フレームの宛先MACアドレスはゼロです。
D. フレームの宛先MACアドレスが不明です。
Answer: B

NEW QUESTION: 3
내부 감사 부서는 최근 전체 감사 프로그램의 일부로 품질 보증 (QA) 프로그램을 수립했습니다. 다음 중 QA 프로그램 요구 사항의 일부로 가장 중요한 활동은 무엇입니까?
A. 비즈니스 라인의 사용자 만족도 보고서 분석
B. 정기적으로 감사 기준 검토
C. 내부 감사 인력을 위한 장기 계획 수립
D. 시정 조치 계획 실행
Answer: D

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: E

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