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NEW QUESTION: 1
Your network consists of one Active Directory domain. Your company has an intranet.
You deploy Terminal Services terminal servers that run Windows Server 2008.
You plan to make applications available to users on the intranet.
You need to recommend a solution to ensure that each user session receives an equal share of the CPU resources on the terminal servers.
What should you recommend?
A. Install and configure the Terminal Services server role with the Terminal Services Session Broker (TS Session Broker) services role on all terminal servers.
B. Install the Windows System Resource Manager (WSRM) feature on all terminal servers. Set the resource-allocation policy.
C. Install the Network Policy and Access Services (NPAS) server role on another server. Define and apply a new policy by using Network Policy Server (NPS).
D. Install and configure the Network Load Balancing feature on all terminal servers.
Answer: B
Explanation:
To ensure that each user session receives an equal share of the CPU resources on the terminal servers,
you need to install the Windows System Resource Manager (WSRM) feature on all terminal servers and
configure a resource-allocation policy.
Windows System Resource Manager (WSRM) on Windows Server 2008 allows you to control how CPU
and memory resources are allocated to applications, services, and processes on the computer. WSRM
uses resource-allocation policies to determine how computer resources, such as CPU and memory, are
allocated to processes running on the computer.
Network Load Balancing and TS Session Load Balancing allows you to balance client requests and use
sessions load but not allow you to control the CPU and memory resources allocated to applications on a
Terminal server. Network Policy Server allows you to configure health policies for network access and
therefore cannot be used here.
Reference: Terminal Services and Windows System Resource Manager
http://technet2.microsoft.com/windowsserver2008/en/library/36edff58-463f-466e-9c9bcd7b82422d3c1033.mspx?mfr=true

NEW QUESTION: 2
Your company has three offices. The offices are located in Montreal, Toronto, and Vancouver.
The network contains two Active Directory forests named contoso.com and adatum.com. The contoso.com
forest contains one domain. The adatum.com forest contains two domains. All of the servers in
adatum.com are located in the Toronto office. The servers in contoso.com are located in the Montreal and
Vancouver offices. All of the servers in both of the forests run Windows Server 2012 R2.
A two-way, forest trusts exists between the forests.
Each office contains DHCP servers and DNS servers.
You are designing an IP Address Management (IPAM) solution to manage the network.
You need to recommend a solution for the placement of IPAM servers to manage all of the DHCP servers
and all of the DNS servers in both of the forests. The solution must minimize the number of IPAM servers
deployed.
What should you recommend?
A. One IPAM server in each office
B. Two IPAM servers in the Toronto office and one IPAM server in the Montreal office
C. One IPAM server in the Montreal office and one IPAM server in the Toronto office
D. Two IPAM servers in the Toronto office, one IPAM server in the Montreal office, and one IPAM server
in the Vancouver office
E. One IPAM server in the Toronto office
Answer: C
Explanation:
Explanation/Reference:
Explanation:
* There are three general methods to deploy IPAM servers:
Distributed: An IPAM server deployed at every site in an enterprise.

Centralized: One IPAM server in an enterprise.

Hybrid: A central IPAM server deployed with dedicated IPAM servers at each site.

NEW QUESTION: 3
The primary task of demand management in an assemble-to-order environment is to define the:
A. raw materials required to complete the customer's order.
B. customer's order in terms of product families.
C. customer's order in terms of specific components and options.
D. availability of inventory to meet the customer's order.
Answer: C

NEW QUESTION: 4
Given the code fragment:
int b = 3;
if ( !(b > 3)) {
System.out.println("square ");
}{
System.out.println("circle ");
}
System.out.println("...");
What is the result?
A. squarecircle...
B. Compilation fails.
C. square...
D. circle...
Answer: A