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NEW QUESTION: 1

A. Option C
B. Option A
C. Option D
D. Option B
Answer: D
Explanation:
1. Click General ledger > Setup > Ledger.
2. Select a chart of accounts.
3. To add an account structure to the ledger, click Add, and then double-click an account structure. You can also
click Configure account structures to create account structures.
You must select at least one account structure before you can record a source document or journal entry for the legal
entity that the ledger is created for.
4. Optional: Select the financial dimension that must be balanced in all accounting entries. If you select a
balancing financial dimension, you must select a financial dimension that is included in all account structures that are
assigned to the ledger.
5. Select a fiscal calendar for the legal entity.
6. Select an accounting currency and a reporting currency for the legal entity.
7. Select default exchange rate and budget exchange rate types.
8. For each posting type, select a main account. When a currency is revalued, the differences are posted to this
account, depending on the posting type.
Reference: Set up a ledger [AX 2012]

NEW QUESTION: 2

Answer:
Explanation:

Explanation

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT
c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: D
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1