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NEW QUESTION: 1
As shown in the broadcast network, OSPF runs on four routers and in the same area and on the same network segment. OSPF automatically elects a DR. Multiple BDRs to achieve better backup results.

A. False
B. True
Answer: A

NEW QUESTION: 2



A. Option C
B. Option B
C. Option A
D. Option E
E. Option D
Answer: C
Explanation:
The output is from "show conn" command on an ASA. This is another example output I've simulated ciscoasa# show conn
20 in use, 21 most used
UDP OUTSIDE 172.16.0.100:53 INSIDE 10.10.10.2:59655, idle 0:00:06, bytes 39, flags -

NEW QUESTION: 3
Which of the following can result in failure to mount a file system? (Choose all that apply.)
A. Incorrect shared path in the mount command
B. An oversized file system
C. The file system is already deleted
D. Incorrect DNS settings for accessing the file system
Answer: C,D

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: D