C_TS4FI_2020 Test Price - SAP Real C_TS4FI_2020 Question, Pdf C_TS4FI_2020 Format - Sapsam

  • Exam Code: C_TS4FI_2020
  • Exam Name: SAP Certified Application Associate - SAP S/4HANA for Financial Accounting Associates (SAP S/4HANA 2020)
  • Version: V15.35     Q & A: 208 Questions and Answers

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NEW QUESTION: 1
Communication is the key to the success of a project. As the project manager, you have four stakeholders with whom you need to communicate. As such, you have six channels of communication. A new stakeholder has been added that you also need to communicate with. How many communication channels do you have now?
A. 0
B. 1
C. 2
D. 3
Answer: B
Explanation:
5*4/2 = 10, If you are the PM and have four stakeholders to communicate with, there are 5 people involved and 10 channels. When you add a new stakeholder, you have 6 people and 15 channels. The formula stated in this question is N(N-1)/2 where N equals the number of people. How to derive this Formula: The Attached calculation will help to realize the concept of communication channel. Say, there are "n" Persons and they are having communication with each other. We need to find how many communication channels are possible here. Take the case of the first person. He can communicate with rest of the (n-1) person. So, here are (n-1) communication channels. The Second person can communicate with ((n-1)-1) person because his communication with the first person is already taken into account for the calculation of first person. So, here are (n-2) communication channels. Similarly, the third person can communicate with ((n-1)-2) because his communication with the first and second person is already taken into account for the calculation of first and second person. So, it's (n-3) channels.Like that, if we proceed, the total no of Channels used by n person, will be = (n-1)+(n-2)+(n-3)+......+1 = 1+2+3+.....+(n-1)We have a sum of an AP series for "(n-1)" number whose first number is "1" and the common difference is also "1".The Formula for Sum of AP series is: S = n[2a+(n-1)d]/2(where, n = total numbers, a = first number, d = common difference) So, it gives us the Total Communication Channel=(n-1) *[2*1+((n-1)-1)*1]/2 = (n1)*[2+(n-2)]/2 = n*(n-1)/2 Hope this helps.

NEW QUESTION: 2
Examine this query executed as SYS and its output:

Which two observations are true based on the output?
A. All distinct query results are cached for the duration of a SYS user session.
B. Repetitive SQL queries and PL/SQL function results are cached and automatically used from the cache across all SYS user sessions.
C. Repetitive SQL queries executed on permanent non-dictionary objects may have faster response times.
D. The result cache exists but which SQL queries are cached depends on the value of the RESULT_CACHE_MODE parameter.
E. The client-side result cache and the server-side result cache are enabled.
Answer: C,D

NEW QUESTION: 3
Eine Bank wählt einen Server für ihre Privatkundenanwendung aus. Welchen Test sollte der IS-Prüfer empfehlen, um sicherzustellen, dass der Server ein hohes Transaktionsvolumen mit den erforderlichen Antwortzeiten verarbeiten kann?
A. Integration
B. Benchmark
C. Regression
D. Annahme
Answer: B

NEW QUESTION: 4
Welche der folgenden Maßnahmen ist am hilfreichsten, um sich vor Hacking-Versuchen im Produktionsnetzwerk zu schützen?
A. SIEM-Tools (Security Information and Event Management)
B. Dezentrale Honeypot-Netzwerke
C. Netzwerkpenetrationstest
D. Intrusion Prevention-Systeme
Answer: B

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