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NEW QUESTION: 1
The ANSI restriction that only 239 Fibre Channel domains are allowed per SAN fabric creates challenges for the designer working on a Cisco Data Center Unified Fabric network.
Which two approaches can the designer utilize to restrict the number of Fibre Channel domains below
239? (Choose two.)
A. Migrate to FCoE to eliminate the need for Fibre Channel domains.
B. Assign a domain ID for each blade switch and top-of-rack access layer switch.
C. Use NPV to cause a fabric or blade switch to appear as a host to the core Fibre Channel switch.
D. Daisy chain up to 100 core Fibre Channel switches, leaving 139 domains for the network edge.
E. Utilize VSANs to allow scaling well beyond 239 domain IDs.
Answer: C,E

NEW QUESTION: 2
ルーターのイーサネットポートに172.16.112.1/20のIPアドレスが割り当てられている場合、このサブネットで許可されるホストの最大数はいくつですか？
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: C
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 ,
8, 4, 2, 1
Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255.
The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2