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NEW QUESTION: 1
James is creating an IBM LotusScript agent that will concatenate a string value and a numeric expression. Using the following code snippet, what will be the output? a$ = "500" b% = 200 c$ = "100" print (a$ & b%) + c$
A. 0
B. 1
C. 2
D. 3
Answer: D

NEW QUESTION: 2
Which of the following statements is FALSE regarding the MG-ISM module on an Alcatel-Lucent 7750 MG?
A. On an Alcatel-Lucent 7750 MG, two MG-ISM modules can be configured as 1+1 redundant.
B. The MG-ISM module implements the PCC rules for the EPS bearers.
C. The MG-ISM module can be configured as a SGW/SGSN or a PGW/GGSN.
D. The switchover from the active MG-ISM card to the standby MG-ISM card has no impact on other EPC nodes
E. The MG-ISM module enforces the QoS rules for the EPS bearers.
Answer: C

NEW QUESTION: 3
Which of the following is/are true?
I. If a test always rejects the null, its significance level is zero.
II. If a test always accepts the null, the probability of type II error equals zero.
III. If the p-value exceeds the significance level, you cannot reject the null.
A. I only
B. II only
C. III only
D. II & III
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The lowest significance level at which the null hypothesis can be rejected is called the p-value of the test.
Thus, if the p-value is less than the significance level, the null hypothesis can be rejected at that significance level; otherwise, you must fail to reject the null. The significance level in hypothesis testing refers to the probability that we will reject the null when it is true. Hence, if we always reject the null, the probability of rejecting it when it is true equals 1. A Type II error occurs when we fail to reject the null when in fact it is false. Therefore, if we always accept the null, we will never reject it even when it is false. So the probability of Type II error will equal 1.

NEW QUESTION: 4
Consider the Orders relation shown in the exhibit. Which of the following SQL statements would replace the value in the Sales_Rep_No column with 110 everywhere that Sales_Rep_No 108 is listed?

A. UPDATE Orders
WHERE Sales_Rep_No = 108
SET Sales_Rep_No = 110;
B. UPDATESales_Rep_No IN Orders SET(Sales_Rep_No = 110 WHERE Sales_Rep_No = 108);
C. UPDATE Orders
SET Sales_Rep_No = 110;
D. UPDATE Orders SET Sales_Rep_No = 110 WHERE Sales_Rep_No = 108;
Answer: D