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NEW QUESTION: 1
Which of the following is not a valid reason for a packet to be punted?
A. A packet belonging to a GRE tunnel
B. A Telnet packet from a session being initiated with the switch
C. The TCAM has reached capacity
D. Routing protocols sending broadcast traffic
E. An unknown destination MAC address
F. A packet being discarded due to a security violation
Answer: F
Explanation:
Reference: CCNP TSHOOT Certification Guide: Advanced Cisco CatalystSwitch
Troubleshooting

NEW QUESTION: 2
The most common computer-related problem confronting organizations is:
A. Hardware malfunction.
B. Fraud.
C. Input errors and omissions.
D. Disruption to computer processing caused by natural disasters.
Answer: C
Explanation:
The most common problem confronting an organization in its use of computers is erroneous or incomplete input. Input is especially susceptible to errors and omissions because of the substantial human intervention required. Comprehensive and effective input controls are necessary ensure that data stored in files or used in processing are not contaminated.

NEW QUESTION: 3
Like OSPFv2, OSPFv3 supports virtual links.Which two statements are true about the IPv6 address of a virtual neighbor? (Choose two.)
A. It is the link-local address, and it is discovered by examining link LSA received by the virtual neighbor.
B. It is the global scope address, and it is discovered by examining the intra-area-prefix-LSAs received by the virtual neighbor.
C. It is the link-local address, and it is discovered by examining the hello packets received from the virtual neighbor.
D. Only prefixes with the LA-bit not set can be used as a virtual neighbor address.
E. It is the global scope address, and it is discovered by examining the router LSAs received by the virtual neighbor.
F. Only prefixes with the LA-bit set can be used as a virtual neighbor address.
Answer: B,F

NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
B. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL
C. SELECT COUNT(*)
FROM (SELECT CustNo
FROMtblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
D. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
G. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcct D, tblLoanAcct L
WHERE D.CustNo = L.CustNo
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Would list the customers with duplicates, which would equal the number of accounts.
Incorrect Answers:
A: INTERSECT returns distinct rows that are output by both the left and right input queries operator.
B: Would list the customers without duplicates.
D: Number of customers.
F: EXCEPT returns distinct rows from the left input query that aren't output by the right input query.
References:
https://msdn.microsoft.com/en-us/library/ms180026.aspx