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NEW QUESTION: 1
Customers expect their virtual environment network and storage I / O traffic will be very large . They are interested in the I / O load separation. They also hope to be in the case of the VIO server without downtime for maintenance.
Which option to meet the requirements ?
A. (2) VIO server , wherein a processing network , a processing memory
B. (2) VIO servers , each handling a part of the flow
C. (4) VIO server , wherein two processing network , handling two storage
D. (4) VIO servers , each handling a part of the flow
Answer: C

NEW QUESTION: 2
DRAG DROP
You have an Exchange Server 2013 organization that contains three servers named EX1, EX2, and EX3. The servers are members of a database availability group (DAG) named DAG1. A mailbox database named DB1 is replicated to all the members of DAG1.
EX3 experiences a complete hardware failure.
You need to restore EX3 on a new server. You reset the computer account for EX3.
Which three actions should you perform next?
To answer, move the three appropriate actions from the list of actions to the answer area and arrange them in the correct order.

Answer:
Explanation:

NEW QUESTION: 3
Which single Cisco IOS ACL entry permits IP addresses from 172.16.80.0 to 172.16.87.255?
A. permit 172.16.80.0 255.255.240.0
B. permit 172.16.80.0 0.0.248.255
C. permit 172.16.80.0 0.0.3.255
D. permit 172.16.80.0 0.0.7.255
E. permit 172.16.80.0 255.255.248.0
F. permit 176.16.80.0 255.255.252.0
Answer: D
Explanation:
www.cisco.com/en/US/products/sw/secursw/ps1018/products_tech_note09186a00800a5b 9a.shtml ACL Summarization Note: Subnet masks can also be represented as a fixed length notation. For example, 192.168.10.0/24 represents 192.168.10.0 255.255.255.0. This list describes how to summarize a range of networks into a single network for ACL optimization. Consider these networks. 192.168.32.0/24 192.168.33.0/24 192.168.34.0/24 192.168.35.0/24 192.168.36.0/24 192.168.37.0/24 192.168.38.0/24 192.168.39.0/24
The first two octets and the last octet are the same for each network. This table is an explanation of how to summarize these into a single network.
The third octet for the previous networks can be written as seen in this table, according to the octet bit position and address value for each bit.
Decimal 128 64 32 16 8 4 2 1 32 0 0 1 0 0 0 0 0 33 0 0 1 0 0 0 0 1 34 0 0 1 0 0 0 1 0 35 0 0 1 0 0 0 1 1 36 0 0 1 0 0 1 0 0 37 0 0 1 0 0 1 0 1 38 0 0 1 0 0 1 1 0 39 0 0 1 0 0 1 1 1 M M M M M D D D
Since the first five bits match, the previous eight networks can be summarized into one network (192.168.32.0/21 or 192.168.32.0 255.255.248.0). All eight possible combinations of the three low-order bits are relevant for the network ranges in question. This command defines an ACL that permits this network. If you subtract 255.255.248.0 (normal mask) from 255.255.255.255, it yields 0.0.7.255. access-list acl_permit permit ip 192.168.32.0 0.0.7.255

NEW QUESTION: 4
Which two commands add VLAN 20 to the VLAN configuration file? (Choose two.)
A. switch(config-if)#switchport access vlan 20
B. switch(config)#vlan 20
C. switch(config-if)#switchport trunk allowed vlan 20
D. switch(config)#vlan configuration 20
E. switch(config)#interface vlan 20
Answer: B,E