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NEW QUESTION: 1
Amazon Cognito에서 모바일 앱은 제공자의 SDK를 사용하여 자격 증명 제공자 (IdP)로 인증합니다.
최종 사용자가 IdP로 인증되면 IdP에서 반환 된 OAuth 또는 OpenID Connect 토큰이 앱에서 Amazon Cognito로 전달되어 사용자에 대한 새 _____ 및 임시 제한된 권한 AWS 자격 증명 세트를 반환합니다.
A. 인식 키 페어
B. Cognito API
C. Cognito SDK
D. 인식 ID
Answer: D
Explanation:
Explanation
Your mobile app authenticates with the identity provider (IdP) using the provider's SDK. Once the end user is authenticated with the IdP, the OAuth or OpenID Connect token returned from the IdP is passed by your app to Amazon Cognito, which returns a new Cognito ID for the user and a set of temporary, limited-privilege AWS credentials.
http://aws.amazon.com/cognito/faqs/

NEW QUESTION: 2
Refer to the exhibit.

What does router R1 use as its OSPF router-ID?
A. 10.10.1.10
B. 10.10.10.20
C. 172.16.15.10
D. 192.168.0.1
Answer: C

NEW QUESTION: 3
Sie haben eine Datenbank, die die folgenden Tabellen enthält.

Sie müssen eine Abfrage erstellen, die jede Beschwerde, die Namen der Mitarbeiter, die die Beschwerde bearbeiten, und die Notizen zu jeder Interaktion zurückgibt. Das Feld Beschwerde muss zuerst angezeigt werden, gefolgt vom Namen des Mitarbeiters und den Notizen. Reklamationen müssen auch dann zurückgesandt werden, wenn keine Interaktion stattgefunden hat.
Erstellen Sie die Abfrage anhand der folgenden Richtlinien:
- Verwenden Sie zweiteilige Spaltennamen.
- Verwenden Sie einteilige Tabellennamen.
- Verwenden Sie den ersten Buchstaben des Tabellennamens als Alias.
- Transact-SQL-Funktionen nicht ausführen.
- Verwenden Sie keine impliziten Joins.
- Umschließen Sie Objektnamen nicht mit eckigen Klammern.
Ein Teil des richtigen Transact-SQL wurde im Antwortbereich unten bereitgestellt. Geben Sie den Code in den Antwortbereich ein, der das Problem löst und die angegebenen Ziele oder Anforderungen erfüllt. Sie können Code sowohl innerhalb als auch unterhalb des bereitgestellten Codes hinzufügen.

1 WÄHLEN Sie c.Beschwerde, e.Name, i.Hinweise
2 VON BESCHWERDEN c
3 BEITRETEN
4 BEITRETEN

Answer:
Explanation:
see explanation below.
Explanation
1 SELECT c.Complaint, e.Name, i.Notes
2 FROM Complaints c
3 JOIN Interactions i ON c.ComplaintID = i.ComplaintID
4 JOIN Employees e ON i.EmployeeID = E.EmployeeID