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NEW QUESTION: 1
The term "WAN" is commonly used when describing which of the following networks?
A. Local Wi-Fi network
B. Internet
C. Ad hoc Wi-Fi network
D. Mesh
Answer: B

NEW QUESTION: 2
Within the OSI model, at what layer are some of the SLIP, CSLIP, PPP control functions provided?
A. Application
B. Presentation
C. Transport
D. Data Link
Answer: D
Explanation:
RFC 1661 - The Point-to-Point Protocol (PPP) specifies that the Point-to-Point
Protocol (PPP) provides a standard method for transporting multi-protocol datagrams over point-
to-point links. PPP is comprised of three main components:
1 A method for encapsulating multi-protocol datagrams.
2 A Link Control Protocol (LCP) for establishing, configuring, and testing the data-link connection.
3 A family of Network Control Protocols (NCPs) for establishing and configuring different network-
layer protocols.

NEW QUESTION: 3
You support Skype for Business Server 2015 servers in your customer's network. The network includes two branches connected with an 8 megabits per second (Mbps) network circuit. The circuit has 1 Mbps of dedicated bandwidth for Skype for Business voice traffic. The network is required to handle 50 peer-to-peer (P2P) calls at a minimum.
Users report that calls between the branches are being dropped, and voice quality is degraded.
Skype for Business audio codecs:

You need to calculate appropriate bandwidth for the P2P call volume required.
What is the minimum dedicated bandwidth that should you allocate?
A. 2.305 Mbps
B. 1.990 Mbps
C. 2.215 Mbps
D. 1.275 Mbps
E. 1.465 Mbps
Answer: E
Explanation:
Explanation
References:
https://technet.microsoft.com/en-us/library/jj688118(v=ocs.15).aspx

NEW QUESTION: 4
Expected monetary value (EMV) is computed by which equation?
A. Multiplying the value of each possible outcome by the probability of occurrence and adding the products together
B. Value of each possible outcome multiplied by probability of non-occurrence
C. Value of each possible outcome multiplied by probability of occurrence
D. Multiplying the value of each possible outcome by the probability of non-occurrence and adding the products together
Answer: A