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NEW QUESTION: 1

A. NFS
B. FCP
C. iSCSI
D. CIFS
E. FTP
Answer: A,C,E
Explanation:
http://backdrift.org/man/netapp/man1/na_sysstat.1.html
sysstat [ -c count ] [ -s ] [ -u | -x | -m | -f | -i | -b ] [ -d ] [ interval ]
-f For the default format display FCP statistics.
The FCP default output format is as follows:
CPU NFS CIFS FCP Net kB/s Disk kB/s FCP kB/s Cache
in out read write in out age
###% ##### ##### ##### ##### ##### ##### ##### ##### ##### >##

NEW QUESTION: 2
You are responsible for purchasing computer hardware for a school district. You have been looking at various sales brochures advocating various types of memory. What would be one advantage to buying dual-channel memory?
A. It will have more memory capacity than single channel memory.
B. It will reduce memory bottlenecks.
C. It has no advantage over single channel memory.
D. It will be twice as fast as single channel memory.
Answer: B
Explanation:
Dual Channel memory offers two channels for data to move through it. This may reduce
bottle necks.
Answer options B and D are correct. The dual or single channel issue is unrelated to
memory speed or capacity.
Answer option C is incorrect. It will have an advantage over single channel, though the
advantages are slight.
Reference: http://www.pcextreme.net/reviews/ram/dual-channel-vs-single-memory-
configuration/

NEW QUESTION: 3
프로젝트 팀원은 새로운 규정으로 인해 요구 사항을 변경해야 함을 나타내며 필수 변경을 진행합니다. 다음에 프로젝트 관리자는 어떻게 해야 합니까?
A. 진행할 자원이 충분한 지 판단 할 수 있도록 변경 요청을 스폰서에게 전달하십시오.
B. 변경 관리 계획에 설명 된 프로세스를 따르십시오.
C. 변경이 필요하므로 수정을 수락하십시오.
D. 예산 변경이 가능한지 결정하고 가능한 경우 진행하십시오.
Answer: B

NEW QUESTION: 4
The developer wants to write a criteria query that will return the number of orders made by customer of each county.
Assume that customer is an entity with a unidirectional one-to-many relationship to the Order entity and that Address is an embeddable class, with an attribute country of type String.
Which one of the queries below correctly achieves this?
A. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.multiselect(cb.count(0), c,get(customer_.address.get(address_.country)
cq.groupBy (c.get(customer_.address) .get(address_.country))
B. CriteriaBuilder cb = ...
CriteriaQuery cq = cb.createQueryO;
Root<Customer> c = cq.from(Customer.class);
Root<Customer> c = cq . from (Customer . class ) ,-
Join<Customer, Order> o = c.join(Customer_.orders);
Join<Address, String> country= c.join(Customer,.address) .join(Address
cq.multiselect(cq.count(o), country );
cq.groupBy(c.get(Customer.address)- get (Address_ . country) ) ;
C. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Custower> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(cb.count(o));
cq.groupBy(c.qet(Customer__.address) - get(Address_.country)) ;
D. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class); cq.select (cb.count(c.join
(customer_. Orders)) , c.get(customers(0), c.get(customer_.address) . get (Address_'country));
(c.get(Customer_.address). get(address_.country));
Answer: A
Explanation:
Reference:http://www.jarvana.com/jarvana/view/org/apache/openjpa/openjpa-persistencejdbc/2.0.0/openjpa-persistence-jdbc-2.0.0-testsources.jar!/org/apache/openjpa/persistence/criteria/TestTypesafeCriteria.java?format=ok