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NEW QUESTION: 1
Your network contains an Active Directory forest named contoso.com.
The forest contains a single domain. The domain contains three domain controllers.
The domain controllers are configured as shown in the following table.

You discover that when you run Group Policy Results from Group Policy Management, the settings from site-linked Group Policy objects (GPOs) fail to appear in the results.
You need to ensure that the settings from site-linked GPOs appear in the results.
What should you do first?
A. Run adprep on DC3 by using Windows Server 2012 R2 installation media.
B. Run adprep on DC1 by using Windows Server 2003 installation media.
C. Transfer the infrastructure master role to DC3.
D. Upgrade DC2 to Windows Server 2012 R2.
Answer: A
Explanation:
In this scenario a Windows 2012 server has been added to a Windows 2003 network.
Note:
* Before adding your new Windows 2012 Domain Controller, or attempting to perform an inplace upgrade of an existing Windows 2008 or 2008 R2 DC, you must make sure that the Schema is upgraded to support your new Windows 2012 DC, and that you prepare each domain where you plan to install Windows 2012 DCs. To do this we can use the ADPREP.exe tool found in the support\adprep folder on your installation media.
* Starting with Windows 2012 there is only one version of ADPREP available, and that is a 64-bit version.
* Adprep is the utility--included in the OS installation media--that performs several crucial functions to upgrade AD to support that OS. The utility has three major options: /forestprep, /domainprep, and
/rodcprep. The /forestprep option runs first, extending the AD schema with new object and attribute classes that the new AD version needs.
The /domainprep option creates new well-known objects in AD, App1ies security changes, and miscellaneous other bits. Finally, /rodcprep makes forest-wide security changes to allow read-only domain controller (RODC) functionality. The Windows Server 2012 R2 version of adprep.exe can run on any server that runs a 64- bit version of Windows Server 2008 or later. Reference: How to add a Windows Server 2012 R2 domain controller to an existing Windows 2008 domain
http://technet.microsoft.com/en-us/library/bb726995.aspx
http://www.ipuptime.net/Multicast.aspx
http://technet.microsoft.com/en-us/library/gg144561(v=exchg.141).aspx
http://en.wikipedia.org/wiki/Unique_local_address

NEW QUESTION: 2
What needs to be done if a 3rd Party Service Contract is due to expire?
A. The Care Program Manager should inform the Service Engagement Manager.
B. Care Program Manager should contact the 3rd Party Service Manager and supplier representatives to renew the contract.
C. Care Program Manager should inform the Customer to renew the contract directly with the supplier.
D. Care Program Manger should inform Product Line.
Answer: B

NEW QUESTION: 3
Which of the following is used to govern the disclosure of financial and accounting information?
A. Sarbanes-Oxley
B. Health Insurance Portability and Accountability Act
C. Gramm-Leach-Bliley Act
D. Privacy act of 1974
Answer: A

NEW QUESTION: 4
SIMULATION



Answer:
Explanation:
Specify appropriate devices and drag them on the "Device" boxes
For the device at the bottom-right box, we notice that it has 2 interfaces Fa0/2 and Fa0/4; moreover the link connects the PC on the right with the device on the bottom-right is a straight-through link -> it is a switch
The question stated that this topology contains 3 routers and 1 switch -> two other devices are routers
Place them on appropriate locations as following:

(Host D and host E will be automatically added after placing two routers. Click on them to access neighboring routers)
Specify appropriate connections between these devices:
+ The router on the left is connected with the Main router through FastEthernet interfaces: use a crossover cable
+ The router on the right is connected with the Main router through Serial interfaces: use a serial cable
+ The router on the right and the Switch: use a straight-through cable
+ The router on the left and the computer: use a crossover cable
(To remember which type of cable you should use, follow these tips:
-To connect two serial interfaces of 2 routers we use serial cable
-To specify when we use crossover cable or straight-through cable, we should remember:
Group 1: Router, Host, Server
Group 2: Hub, Switch
One device in group 1 + One device in group 2: use straight-through cable
Two devices in the same group: use crossover cable
For example, we use straight-through cable to connect switch to router, switch to host, hub to host, hub to server... and we use crossover cable to connect switch to switch, switch to hub, router to router, host to host.)

Assign appropriate IP addresses for interfaces:
From Main router, use show running-config command.

(Notice that you may see different IP addresses in the real CCNA exam, the ones shown above are just used for demonstration)
From the output we learned that the ip address of Fa0/0 interface of the Main router is 192.168.152.177/28. This address belongs to a subnetwork which has:
Increment: 16 (/28 = 255.255.255.240 or 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.168.152.176 (because 176 = 16 * 11 and 176 < 177)
Broadcast address: 192.168.152.191 (because 191 = 176 + 16 - 1)
And we can pick up an ip address from the list that belongs to this subnetwork: 192.168.152.190 and assign it to the
Fa0/0 interface the router on the left
Use the same method for interface Serial0/0 with an ip address of 192.168.152.161
Increment: 16
Network address: 192.168.152.160 (because 160 = 16 * 10 and 160 < 161)
Broadcast address: 192.168.152.175 (because 176 = 160 + 16 - 1)
-> and we choose 192.168.152.174 for Serial0/0 interface of the router on the right
Interface Fa0/1 of the router on the left
IP (of the computer on the left) : 192.168.152.129/28
Increment: 16
Network address: 192.168.152.128 (because 128 = 16 * 8 and 128 < 129)
Broadcast address: 192.168.152.143 (because 143 = 128 + 16 - 1)
-> we choose 192.168.152.142 from the list
Interface Fa0/0 of the router on the right
IP (of the computer on the left) : 192.168.152.225/28
Increment: 16
Network address: 192.168.152.224 (because 224 = 16 * 14 and 224 < 225)
Broadcast address: 192.168.152.239 (because 239 = 224 + 16 - 1)
-> we choose 192.168.152.238 from the list
Let's have a look at the picture below to summarize
Configure two routers on the left and right with these commands:

Router1 = router on the left
Assign appropriate IP addresses to Fa0/0 & Fa0/1 interfaces:
Router1>enable
Router1#configure terminal
Router1(config)#interface fa0/0
Router1(config-if)#ip address 192.168.152.190 255.255.255.240
Router1(config-if)#no shutdown
Router1(config-if)#interface fa0/1
Router1(config-if)#ip address 192.168.152.142 255.255.255.240
Router1(config-if)#no shutdown
Set passwords (configure on two routers)
+ Console password:
Router1(config-if)#exit
Router1(config)#line console 0
Router1(config-line)#password consolepw
Router1(config-line)#login
Router1(config-line)#exit
+ Telnet password:
Router1(config)#line vty 0 4
Router1(config-line)#password telnetpw
Router1(config-line)#login
Router1(config-line)#exit
+ Privilege mode password:
Router1(config)#enable password privpw
Save the configuration:
Router1(config)#exit
Router1#copy running-config startup-config
Configure IP addresses of Router2 (router on the right)
Router2>enable
Router2#configure terminal
Router2(config)#interface fa0/0
Router2(config-if)#ip address 192.168.152.238 255.255.255.240
Router2(config-if)#no shutdown
Router2(config-if)#interface serial0/0
Router2(config-if)#ip address 192.168.152.174 255.255.255.240
Router2(config-if)#no shutdown
Then set the console, telnet and privilege mode passwords for Router2 as we did for Router1, remember to save the configuration when you finished.