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NEW QUESTION: 1
When a switch port sends a data frame with the same VLAN tag and PVID , the switch port removes the VLAN tag and forwards frame.
A. FALSE
B. TRUE
Answer: B

NEW QUESTION: 2
あるキャンパスに2つの建物があり、その敷地は約700フィート（214メートル）離れており、敷地の境界がはっきりしています。建物の間に繊維はありません。ただし、建物内のネットワークを相互に接続する必要があります。 2つの建物間の接続は、1 Gbpsを超えるピークレートをサポートする必要があります。
要件を満たし、費用対効果の高いソリューションを企業が選択する必要があるのはどれですか。
A. 2つの屋外AP 367
B. 2つの屋外AP 387
C. 2つの屋外AP 510
D. キャンパススイッチ間のマルチモードファイバー
Answer: A

NEW QUESTION: 3
Use the following login credentials as needed:
To enter your username, place your cursor in the box and click on the username below.
To enter your password, place your cursor in the box and click on the password below.
Microsoft 365 Username: [email protected]
Microsoft 365 Password: b#nqvZG*0w*4
The following information is for technical support purposes only:
Lab instance: 10658557
A. See explanation below.
B. See explanation below.
You need to ensure that all email sent from the Internet to the mailbox of a user named Admin1 is scanned for malware. The solution must use Dynamic Delivery.
To complete this task, sign in to the Microsoft 365 admin center.
Answer: A,B
Explanation:
Explanation
You need to add an ATP Safe Attachments policy and apply it to Admin1.
1. Go to Security and Compliance Admin Center.
2. Go to the Threat Management section > Policy > ATP Safe Attachments.
3. Click the 'plus' icon to create new policy.
4. Give the policy a name.
5. Select the 'Dynamic Delivery' option.
6. In the 'Applied To' section, in the 'if' section, select "The recipient is".
7. Click the 'Add condition' button and enter Admin1 and save the policy.
References:
https://docs.microsoft.com/en-us/microsoft-365/security/office-365-security/set-up-atp-safe-attachments-policies

NEW QUESTION: 4
You administer a Microsoft SQL Server 2012 database that includes a table named Products. The Products table has columns named Productld, ProductName, and CreatedDateTime. The table contains a unique constraint on the combination of ProductName and CreatedDateTime. You need to modify the Products table to meet the following requirements:
Remove all duplicates of the Products table based on the ProductName column.
Retain only the newest Products row. Which Transact-SQL query should you use?
A. WITH CTEDupRecords AS (
SELECT MIN(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
B. WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
cte.ProductName = p.ProductName
AND cte.CreatedDateTime > p.CreatedDateTime
C. WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
AND p.CreatedDateTime > cte.CreatedDateTime
D. WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
Answer: B
Explanation:
--Burgos - NO I changed answer to B (previous was A) because is imposseble to delete products with CreateDateTime greater than MAX(CreateDateTime). In fact will exists ONE AND ONLY ONE record with CreateDateTime EQUAL TO MAX(CreateDateTime), all records with same ProductName have a lower than MAX (CreateDateTime). I tested both choices anda ONLY B is correct. Use the code below to test (note that SELECT will catch only rows to be deleted:
--Exam A Q028
CREATE TABLE Products (
Productld int identity (1, 1) not null,
ProductName varchar (10) not null,
CreatedDateTime datetime not null,
constraint PK_Products PRIMARY KEY CLUSTERED (Productld)
)
GO
ALTER TABLE Products ADD CONSTRAINT UQ_Products UNIQUE (ProductName,
CreatedDateTime)
GO
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 1', '201010-10')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 1', '201111-11')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 1', '201212-12')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 2', '201010-10')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 2', '201212-12')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 3', '201010-10')
GO
WITH CTEDupRecords AS
(
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
) select p.* FROM Products p JOIN CTEDupRecords cte ON p.ProductName = cte.ProductName AND p.CreatedDateTime > cte.CreatedDateTime GO WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
) select p.* FROM Products p JOIN CTEDupRecords cte ON cte.ProductName = p.ProductName AND cte.CreatedDateTime > p.CreatedDateTime GO
PS: In v.2012-10-17.by.Alex.142q this exercise appears with choice A using "<" instead of ">", so, in Alex we have two correct answers (A and B). --\Burgos
Verified answer as correct.