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NEW QUESTION: 1
A monitor has been defined with an alias port of 443. All other options are left at their defaults.
The administrator wishes to assign it to a pool of members where the members' ports vary. Which is the result?
A. For each member, if the member port is not 443, the member will be marked down. For each member,if the member? Port is not 443, the member will be marked down.
B. This assignment is not allowed since the port do not match.
C. For each member. If it is running an SSL service at the member port, the monitor may work.
Otherwise, the monitor will fail and the member for each member, if it is running an SSL service at the member port, the monitor may work. Otherwise, the monitor will fail and the member will be marked down.
D. For each member, the monitor will test member node at port 443. For each member, the monitor will test the member ? node at port 443.
Answer: D

NEW QUESTION: 2
A company provides web app hosting services for customers.
You have a set of App Service Plans available to deploy resources for new projects. The available service tiers are shown in the Service Tiers exhibit. (Click the Service Tiers tab.)

You must provision resources for the projects as shown in the Projects exhibit. (Click the Projects tab.)

The Adventure Works a project requires the use of deployment slots as shown in the Deployment Slots exhibit. (Click the Deployment Slots tab.)

You need to determine where to deploy resources for each project.
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

NEW QUESTION: 3
-- Exhibit -

-- Exhibit -
Click the Exhibit button.
Referring to the exhibit, you want to configure Switch-1 to allow a user on interface ge-0/0/10 to accommodate both voice and data traffic. Your phones and your switches are LLDP-MED capable.
What is the minimal configuration that allows LLDP-MED to autoconfigure your phone's voice VLAN?
A. set interfaces ge-0/0/10 unit 0 family ethernet-switching port-mode access set interfaces ge-0/0/10 unit 0 family ethernet-switching vlan members data_vlan set ethernet-switching-options voip interface ge-0/0/10.0 forwarding-class assured-forwarding set protocols lldp-med interface ge-0/0/10.0
B. set interfaces ge-0/0/10 unit 0 family ethernet-switching port-mode access set interfaces ge-0/0/10 unit 0 family ethernet-switching vlan members data_vlan set ethernet-switching-options voip interface ge-0/0/10.0 vlan voice_vlan set protocols lldp-med interface ge-0/0/10.0
C. set interfaces ge-0/0/10 unit 0 family ethernet-switching port-mode trunk set interfaces ge-0/0/10 unit 0 family ethernet-switching vlan members voice_vlan set interfaces ge-0/0/10 unit 0 family ethernet-switching native-vlan-id data_vlan set ethernet-switching-options voip interface ge-0/0/10.0 vlan voice_vlan set protocols lldp interface ge-0/0/10.0
D. set interfaces ge-0/0/10 unit 0 family ethernet-switching port-mode trunk set interfaces ge-0/0/10 unit 0 family ethernet-switching vlan members voice_vlan set interfaces ge-0/0/10 unit 0 family ethernet-switching native-vlan-id data_vlan set ethernet-switching-options voip interface ge-0/0/10.0 vlan voice_vlan set protocols lldp-med interface ge-0/0/10.0
Answer: B

NEW QUESTION: 4
The developer wants to write a criteria query that will return the number of orders made by customer of each county.
Assume that customer is an entity with a unidirectional one-to-many relationship to the Order entity and that Address is an embeddable class, with an attribute country of type String.
Which one of the queries below correctly achieves this?
A. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class); cq.select (cb.count(c.join
(customer_. Orders)) , c.get(customers(0), c.get(customer_.address) . get (Address_'country)); (c.get(Customer_.address). get(address_.country));
B. CriteriaBuilder cb = ...
CriteriaQuery cq = cb.createQueryO;
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
Join<Address, String> country = c.join(Customer,.address) .join(Address cq.multiselect(cq.count(o), country );
cq.groupBy(c.get(Customer.address) - get (Address_ . country) ) ;
C. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Custower> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(cb.count(o));
cq.groupBy(c.qet(Customer__.address) - get(Address_.country)) ;
D. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.multiselect(cb.count(0), c,get(customer_.address.get(address_.country) cq.groupBy (c.get(customer_.address) .get(address_.country))
Answer: D
Explanation:
Explanation/Reference:
Incorrect: Not B, Not C: Use multiselect, not select. Not D: Use one Join, not two.
Use multiselect, count and Group By. multiselect() method is used because we are going to get compound result and not one entity type.
Example:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Object[]> query = cb.createQuery(Object[].class);
Root<Department> d = query.from(Department.class);
Join<Department,Teacher> teachers = d.join("teachers");
query.multiselect(d.get("name"),cb.count(teachers)).groupBy(d.get("name")); Reference: Criteria group by clause