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NEW QUESTION: 1
A technician suspects that a recent virus they removed may have corrupted a necessary system file. Which of the following utilities can the technician use to verify the integrity of these critical files?
A. sfc
B. msconfig
C. regsrv32
D. fixmbr
Answer: A

NEW QUESTION: 2
Refer to the exhibit. Customer is planning to deploy a clustering over the WAN UCM topology with 2 subscribers at site 1 and 2 subscribers at site 2.
How much bandwidth would be required between site 1 and site 2 to for database replication?

A. 4.632 Mbps
B. 6.176 Mbps
C. 7.772 Mbps
D. 1.544 Mbps
E. 3.088 Mbps
Answer: A
Explanation:
Consider two sites, Site 1 and Site 2, with Unified CM clustered over the WAN across these two sites that are 80 msec round-trip time apart. Site 1 has one publisher, one combined TFTP and music on hold (MoH) server, and two Unified CM subscriber servers. Site 2 has one TFTP/MoH server and two Unified CM subscriber servers. Site 1 has 5000 phones, each having one DN; and Site 2 has 5000 phones, each having one DN. During the busy hour, 2500 phones in Site 1 call
2500 phones in Site 2, each at 3 BHCA. During that same busy hour, 2500 phones in Site 2 also call 2500 phones in Site 1, each at 3 BHCA. In this case:
Total BHCA during the busy hour = 2500*3 + 2500*3 = 15,000
Total bandwidth required between the sites = Total ICCS bandwidth + Total database bandwidth Because total BHCA is 15,000 (greater than 10,000), we can use the formula to calculate:
Total ICCS bandwidth = (15,000/10,000) * (1 + 0.006*80) = 2.22 Mbps
Total database bandwidth = (Number of servers remote to the publisher) * 1.544 = 3 * 1.544 =
4.632 Mbps
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cucm/srnd/7x/uc7_0/models.html

NEW QUESTION: 3
새로운 애자일 팀이 작업을 완료하는 데 어려움을 겪고 있습니다. 팀에서 많은 분쟁이 발생하고 있습니다. 이 상황에서 애자일 리더는 무엇을 해야 합니까?
A. 역할 및 책임 문서를 검토합니다.
B. 일부 팀원을 제거하십시오.
C. 문제를 팀의 관리자에게 이관합니다.
D. 팀과 작업 계약을 개발합니다.
Answer: A

NEW QUESTION: 4

-10.0.0.100
-131.107.0.100


Answer:
Explanation: