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NEW QUESTION: 1







Answer:
Explanation:
SELECT SensorID, NearestMountain(Location)
FROM GroundSensors
WHERE TREMOR <> 0 AND NormalizedReading IS NOT NULL
GROUP BY SensorID, NearestMountain(Location)
Explanation
GROUP BY is a SELECT statement clause that divides the query result into groups of rows, usually for the purpose of performing one or more aggregations on each group. The SELECT statement returns one row per group.
SELECT SensorID, NearestMountain(Location)
FROM GroundSensors
WHERE TREMOR <> 0 AND NormalizedReading IS NOT NULL
GROUP BY SensorID, NearestMountain(Location)
References: https://msdn.microsoft.com/en-us/library/ms177673.aspx

NEW QUESTION: 2


To allow or prevent load balancing to network 172.16.3.0/24, which of the following commands could be used in R2?
(Choose two.)
A. R2(config-if)#ip ospf cost
B. R2(config-router)#distance ospf
C. R2(config-if)#bandwidth
D. R2(config-if)#ip ospf priority
E. R2(config-if)#clock rate
Answer: A,C
Explanation:
OSPF Cost
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094e9e.shtml#t6
Explanation:
The cost (also called metric) of an interface in OSPF is an indication of the overhead required to send packets across a
certain interface. The cost of an interface is inversely proportional to the bandwidth of that interface. A higher
bandwidth indicates a lower cost. There is more overhead (higher cost) and time delays involved in crossing a 56k
serial line than crossing a 10M ethernet line. The formula used to calculate the cost is:
cost= 10000 0000/bandwith in bps
For example, it will cost 10 EXP8/10 EXP7 = 10 to cross a 10M Ethernet line and will cost 10 EXP8/1544000 =64 to
cross a T1 line.
By default, the cost of an interface is calculated based on the bandwidth; you can force the cost of an interface with
the ip ospf cost <value> interface subconfiguration mode command.

NEW QUESTION: 3
You are developing an HTML5 page that has an element with an ID of picture. The page includes the following HTML.

You need to move the picture element lower on the page by five pixels.
Which two lines of code should you use? (Each correct answer presents part of the solution. Choose two.)
A. document.getEiementById("picture").style.top = "-5px";
B. document.getEIementById("picture").style.position = "relative";
C. document.getEIementById("picture").style.position = "absolute";
D. document.getElementById("picture").style.top = "5px";
Answer: B,D
Explanation:
We use relative position to move the position 5 pixels lower on page.
Using a negative value would move the picture higher on the page.
Note:
* The top property sets or returns the top position of a positioned element.
This property specifies the top position of the element including padding, scrollbar, border and margin.
Syntax
Set the top property:
Object.style.top="auto|length|%|inherit"
Where:
Length defines the top position in length units. Negative values are allowed

NEW QUESTION: 4
コンピュータフォレンジックの技術者は、データベースサーバーの能動的な侵害に対応します。 Joeはまずメモリ内の情報を収集し、ネットワークトラフィックを収集し、最後にハードドライブのイメージを実行します。
ジョーは次のどの手順に従ったのですか？
A. ボラティリティの順位
B. 回復手順
C. インシデントアイソレーション
D. カストディ・チェーン
Answer: A