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NEW QUESTION: 1
-- Exhibit --
interfaces {
ge-0/0/0 {
vlan-tagging;
unit 100 {
vlan-id 100;
family inet {
address 192.168.100.97/30;
}
family iso;
}
unit 200 {
vlan-id 200;
family inet {
address 192.168.100.94/30;
}
family iso;
}
}
fxp0 {
description "MGMT INTERFACE - DO NOT DELETE";
unit 0 {
family inet {
address 10.210.10.11/27;
}
}
}
lo0 {
unit 0 {
family inet {
address 192.168.100.1/32;
}
family iso {
address 49.1111.1921.6801.0001.00;
}
}
}
}
protocols {
isis {
interface ge-0/0/0.100;
interface ge-0/0/0.200;
}
}
-- Exhibit --
Click the Exhibit button.
An operator is unable to establish any IS-IS adjacencies on a router in the network.
Based on the configuration shown in the exhibit, what is the problem?
A. Each network interface needs a unique family ISO address.
B. Interface lo0 must be configured in the IS-IS hierarchy.
C. The IS-IS level for an each interface must be specified.
D. The ISO address for interface lo0 is not in hex format.
Answer: B

NEW QUESTION: 2
To keep costs at a minimum and decrease the completion time by 1-1/2 days, Networks, Inc. should crash activity)
A. AB and CE.
B. AD.
C. DE.
D. AD and AB.
Answer: D
Explanation:
The critical longest) path is A-D-E, which has an expected time of 13 days 5.5 +7.5). However, to decrease the project's completion time by 1.5 days, paths A-B-C-E 4.5 + 1.0 +
6.5 = 12 days) and A-B-D-E 4.5 + .5 + 7.5 = 12.5 days) as well as A-D-E must also be shortened. Hence, A-D-E must be reduced by 1.5 days, A-B-C-E by .5 day, and A-B-D-E by
1.0 day. The only way to decrease A-D-E by 1.5 days is to crash activity. AD 5.5 expected time -4.0 crash time = 1.5 days). Crashing DE results in a 1.0-day saving 7.5 - 6.5) only.
Crashing AB is the efficient way to reduce both A-B-C-E and A-B-D-E by the desired amount of time because it i s hart of both paths. The incremental cost of crashing AB is U $1,000 US $4,000 crash cost - US $3,000 normal cost) to shorten the completion time by
1.0 day 4.5 - 3.5). The alternatives for decreasing both A-B-C-E and A-B-D-E are more costly.

NEW QUESTION: 3
バックグラウンド
Employeeという名前のテーブルを含むHR1という名前のデータベースがあります。
定期的に変化する合計を含む、読み取り専用の履歴レポートがいくつかあります。 レポートは複数のクエリを使用して給与計算費用を見積もります。 クエリは同時に実行されます。 ユーザーは、給与見積もりレポートが常に実行されるとは限らないと報告しています。 データベースを監視して、レポートの実行を妨げる問題を特定する必要があります。
他のアプリケーションをサポートするデータベースサーバーにアプリケーションを配置することを計画しています。 データベースに必要なストレージの量を最小限に抑える必要があります。
従業員テーブル
次のTransact-SQLステートメントを使用して、Employeeテーブルを作成、設定、設定します。

応用
Employeesテーブルを更新するアプリケーションがあります。 アプリケーションは、次のストアドプロシージャを同時に非同期に呼び出します。
- UspA：このストアード・プロシージャーはEmployeeStatus列のみを更新します。
- UspB：このストアドプロシージャは、EmployeePayRate列のみを更新します。
アプリケーションはビューを使用してデータへのアクセスを制御します。 ビューは以下の要件を満たす必要があります。
- ビューがアクセスするテーブル内のすべての列へのユーザーアクセスを許可します。 - ビューから返される行のみに更新を制限します。
示す

ユーザーは、vwEmployeeビューを使用してEmployeeテーブルのデータのみを変更できなければなりません。 ユーザーがカタログビューでビュー定義を表示できないようにする必要があります。
vwEmployeeを作成するときに使用するビュー属性を識別する必要があります。
以下の表で、使用する必要がある属性を識別してください。
注：各列で1つだけ選択してください。

Answer:
Explanation:

Explanation

References: https://msdn.microsoft.com/en-us/library/ms187956.aspx

NEW QUESTION: 4
Which two commands set up the Cos to DSCP maps on Cisco lOS switches? (Choose)
A. mIs gos
B. auto gos global
C. agls mls voip auto
D. gos mls
E. auto gos voip cisco phone
Answer: A,E
Explanation:
https://www.cisco.com/c/en/us/td/docs/switches/lan/catalyst2960x/software/15-
0_2_EX/qos/command_reference/b_qos_152ex_2960-x_cr/b_qos_152ex_2960-
x_cr_chapter_010.html#wp3514062886