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NEW QUESTION: 1
インシデントに続いて、管理者は人事調査のためにサーバーからフォレンジック証拠を収集しています。調査結果の整合性を維持するために、プロセス全体で文書化することが最も重要なベストプラクティスは次のうちどれですか？
A. CoC
B. 利用規定違反
C. データ損失インシデント
D. サーバー構成
Answer: A
Explanation:
Chain of custody is important because if evidence has been altered or it cannot be proven that it was not altered during the time between collection and use in court, then that evidence is less believable or credible than it otherwise would be.

NEW QUESTION: 2
Examine this code:

Which two are valid correlations to the code to avoid or mitigate SQL Injection?
A. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2
DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname
prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2
(400);BEGINv_bind := DBMS_ASSERT.ENQUOTE_LITERAL ('%' | | p_product_name | |
'%');OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE ' | | v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
B. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2
DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname
prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2
(400);BEGINv_bind := '''%' | | p_product_name | | '%''';OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE ' | | v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
C. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2
DEFAULT NULL) ASv_bind VARCHAR2 (400);BEGINv_bind := '%' | | p_prodname | |
'%';FOR rec IN ('SELECT name, price FROM prod_info WHERE name like ' | | v_bind) LOOPDBMS_OUTPUT.PUT_LINE ('Product Info: ' | | rec.name | | ',' | | rec.price);END LOOP;END;
D. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2
DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname
prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2
(400);BEGINv_bind := '%' | | p_product_name | | '%';OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE ' | | v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
E. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2
DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname
prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2
(400);BEGINv_bind := '%' | | p_product_name | | '%';OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE :b' USING v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
Answer: C,D

NEW QUESTION: 3
Which two statements about IS-IS are true? (Choose two.)
A. The default hello interval is 10 seconds and the default hold timer is 30 seconds.
B. The hello interval can be changed on a per-interface basis with the command isis hello- multiplier.
C. Both IS-IS routers need to have the same capabilities in the hello packet in order to form neighbors.
D. Both routers need to have the same hello intervals and hold timers in order to form IS-IS neighbors.
Answer: A,B
Explanation:
Explanation/Reference:
Explanation:
isis hello-interval
To specify the length of time between hello packets that the Cisco IOS software sends, use the isis hello- interval command in interface configuration mode. By default, a value three times the hello interval seconds is advertised as the hold time in the hello packets sent. (Change the multiplier of 3 by specifying the isis hello-multiplier command.) With smaller hello intervals, topological changes are detected faster, but there is more routing traffic.
The default is 10 seconds.
Reference: http://www.cisco.com/c/en/us/td/docs/ios/12_2/iproute/command/reference/fiprrp_r/1rfisis.html

NEW QUESTION: 4
The entity has a fixed assets balance of:
A. US $16
B. US $64
C. US $0
D. US $58
Answer: D
Explanation:
Total assets given as US $100) equals the sum of cash given as US $10), accounts receivable US $26), inventory, and fixed assets. Inventory can be determined because it is included in current, but not quick, assets, and the current and quick ratios are known.
Current assets equal US $42 1.4 current ratio x $30 current liabilities), and the quick assets equal US $36 1 2 quick ratio = $30 current liabilities). Thus, inventory, which is the only difference in this question between current and quick assets, equals US $6 $42 -$36). Fixed assets must then equal US $58 $100 total assets - $10 cash - $26 accounts receivable - $6 inventory).